Solve for p 2x^2+px+4=0

$2 x^{2} + p x + 4 = 0$

Step 1

Move all terms not containing $p$ to the right side of the equation.

Subtract $2 x^{2}$ from both sides of the equation.

$p x + 4 = - 2 x^{2}$

Subtract $4$ from both sides of the equation.

$p x = - 2 x^{2} - 4$

Step 2

Divide each term in $p x = - 2 x^{2} - 4$ by $x$ and simplify.

Divide each term in $p x = - 2 x^{2} - 4$ by $x$ .

$\frac{p x}{x} = \frac{- 2 x^{2}}{x} + \frac{- 4}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{p x}{x} = \frac{- 2 x^{2}}{x} + \frac{- 4}{x}$

Divide $p$ by $1$ .

$p = \frac{- 2 x^{2}}{x} + \frac{- 4}{x}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $x^{2}$ and $x$ .

Factor $x$ out of $- 2 x^{2}$ .

$p = \frac{x (- 2 x)}{x} + \frac{- 4}{x}$

Cancel the common factors.

Raise $x$ to the power of $1$ .

$p = \frac{x (- 2 x)}{x^{1}} + \frac{- 4}{x}$

Factor $x$ out of $x^{1}$ .

$p = \frac{x (- 2 x)}{x \cdot 1} + \frac{- 4}{x}$

Cancel the common factor.

$p = \frac{x (- 2 x)}{x \cdot 1} + \frac{- 4}{x}$

Rewrite the expression.

$p = \frac{- 2 x}{1} + \frac{- 4}{x}$

Divide $- 2 x$ by $1$ .

$p = - 2 x + \frac{- 4}{x}$

Move the negative in front of the fraction.

$p = - 2 x - \frac{4}{x}$