Solve for p 3(1+p)=-5(p+1)

$3 (1 + p) = - 5 (p + 1)$

Step 1

Simplify $3 (1 + p)$ .

Start simplifying.

$0 + 0 + 3 (1 + p) = - 5 (p + 1)$

Simplify by adding zeros.

$3 (1 + p) = - 5 (p + 1)$

Apply the distributive property.

$3 \cdot 1 + 3 p = - 5 (p + 1)$

Multiply $3$ by $1$ .

$3 + 3 p = - 5 (p + 1)$

Step 2

Simplify $- 5 (p + 1)$ .

Apply the distributive property.

$3 + 3 p = - 5 p - 5 \cdot 1$

Multiply $- 5$ by $1$ .

$3 + 3 p = - 5 p - 5$

Step 3

Move all terms containing $p$ to the left side of the equation.

Add $5 p$ to both sides of the equation.

$3 + 3 p + 5 p = - 5$

Add $3 p$ and $5 p$ .

$3 + 8 p = - 5$

Step 4

Move all terms not containing $p$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$8 p = - 5 - 3$

Subtract $3$ from $- 5$ .

$8 p = - 8$

Step 5

Divide each term in $8 p = - 8$ by $8$ and simplify.

Divide each term in $8 p = - 8$ by $8$ .

$\frac{8 p}{8} = \frac{- 8}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 p}{8} = \frac{- 8}{8}$

Divide $p$ by $1$ .

$p = \frac{- 8}{8}$

Simplify the right side.

Divide $- 8$ by $8$ .

$p = - 1$