Solve for p -3(2+4p)=2(2p-1)

$- 3 (2 + 4 p) = 2 (2 p - 1)$

Simplify $- 3 (2 + 4 p)$ .

Start simplifying.

$0 + 0 - 3 (2 + 4 p) = 2 (2 p - 1)$

Simplify by adding zeros.

$- 3 (2 + 4 p) = 2 (2 p - 1)$

Apply the distributive property.

$- 3 \cdot 2 - 3 (4 p) = 2 (2 p - 1)$

Multiply.

Multiply $- 3$ by $2$ .

$- 6 - 3 (4 p) = 2 (2 p - 1)$

Multiply $4$ by $- 3$ .

$- 6 - 12 p = 2 (2 p - 1)$

Simplify $2 (2 p - 1)$ .

Apply the distributive property.

$- 6 - 12 p = 2 (2 p) + 2 \cdot - 1$

Multiply.

Multiply $2$ by $2$ .

$- 6 - 12 p = 4 p + 2 \cdot - 1$

Multiply $2$ by $- 1$ .

$- 6 - 12 p = 4 p - 2$

Move all terms containing $p$ to the left side of the equation.

Subtract $4 p$ from both sides of the equation.

$- 6 - 12 p - 4 p = - 2$

Subtract $4 p$ from $- 12 p$ .

$- 6 - 16 p = - 2$

Move all terms not containing $p$ to the right side of the equation.

Add $6$ to both sides of the equation.

$- 16 p = - 2 + 6$

Add $- 2$ and $6$ .

$- 16 p = 4$

Divide each term in $- 16 p = 4$ by $- 16$ and simplify.

Divide each term in $- 16 p = 4$ by $- 16$ .

$\frac{- 16 p}{- 16} = \frac{4}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 p}{- 16} = \frac{4}{- 16}$

Divide $p$ by $1$ .

$p = \frac{4}{- 16}$

Simplify the right side.

Cancel the common factor of $4$ and $- 16$ .

Factor $4$ out of $4$ .

$p = \frac{4 (1)}{- 16}$

Cancel the common factors.

Factor $4$ out of $- 16$ .

$p = \frac{4 \cdot 1}{4 \cdot - 4}$

Cancel the common factor.

$p = \frac{4 \cdot 1}{4 \cdot - 4}$

Rewrite the expression.

$p = \frac{1}{- 4}$

Move the negative in front of the fraction.

$p = - \frac{1}{4}$

The result can be shown in multiple forms.

Exact Form:

$p = - \frac{1}{4}$

Decimal Form:

$p = - 0.25$

Solve for p -3(2+4p)=2(2p-1)

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