Solve for p -3(2+4p)=42

$- 3 (2 + 4 p) = 42$

Step 1

Divide each term in $- 3 (2 + 4 p) = 42$ by $- 3$ and simplify.

Divide each term in $- 3 (2 + 4 p) = 42$ by $- 3$ .

$\frac{- 3 (2 + 4 p)}{- 3} = \frac{42}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (2 + 4 p)}{- 3} = \frac{42}{- 3}$

Divide $2 + 4 p$ by $1$ .

$2 + 4 p = \frac{42}{- 3}$

Simplify the right side.

Divide $42$ by $- 3$ .

$2 + 4 p = - 14$

Step 2

Move all terms not containing $p$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$4 p = - 14 - 2$

Subtract $2$ from $- 14$ .

$4 p = - 16$

Step 3

Divide each term in $4 p = - 16$ by $4$ and simplify.

Divide each term in $4 p = - 16$ by $4$ .

$\frac{4 p}{4} = \frac{- 16}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 p}{4} = \frac{- 16}{4}$

Divide $p$ by $1$ .

$p = \frac{- 16}{4}$

Simplify the right side.

Divide $- 16$ by $4$ .

$p = - 4$