Solve for p 32>=-16p

$32 \geq - 16 p$

Step 1

Rewrite so $p$ is on the left side of the inequality.

$- 16 p \leq 32$

Step 2

Divide each term in $- 16 p \leq 32$ by $- 16$ and simplify.

Divide each term in $- 16 p \leq 32$ by $- 16$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 16 p}{- 16} \geq \frac{32}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 p}{- 16} \geq \frac{32}{- 16}$

Divide $p$ by $1$ .

$p \geq \frac{32}{- 16}$

Simplify the right side.

Divide $32$ by $- 16$ .

$p \geq - 2$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$p \geq - 2$

Interval Notation:

$[- 2, \infty)$

Solve for p 32>=-16p

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