Solve for p -4+6p+18+3p=9(p+1)+5

$- 4 + 6 p + 18 + 3 p = 9 (p + 1) + 5$

Simplify $- 4 + 6 p + 18 + 3 p$ .

Add $- 4$ and $18$ .

$6 p + 14 + 3 p = 9 (p + 1) + 5$

Add $6 p$ and $3 p$ .

$9 p + 14 = 9 (p + 1) + 5$

Simplify $9 (p + 1) + 5$ .

Simplify each term.

Apply the distributive property.

$9 p + 14 = 9 p + 9 \cdot 1 + 5$

Multiply $9$ by $1$ .

$9 p + 14 = 9 p + 9 + 5$

Add $9$ and $5$ .

$9 p + 14 = 9 p + 14$

Move all terms containing $p$ to the left side of the equation.

Subtract $9 p$ from both sides of the equation.

$9 p + 14 - 9 p = 14$

Combine the opposite terms in $9 p + 14 - 9 p$ .

Subtract $9 p$ from $9 p$ .

$0 + 14 = 14$

Add $0$ and $14$ .

$14 = 14$

Since $14 = 14$ , the equation will always be true for any value of $p$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$