Solve for p (4p)/6+27=39

$\frac{4 p}{6} + 27 = 39$

Step 1

Cancel the common factor of $4$ and $6$ .

Factor $2$ out of $4 p$ .

$\frac{2 (2 p)}{6} + 27 = 39$

Cancel the common factors.

Factor $2$ out of $6$ .

$\frac{2 (2 p)}{2 (3)} + 27 = 39$

Cancel the common factor.

$\frac{2 (2 p)}{2 \cdot 3} + 27 = 39$

Rewrite the expression.

$\frac{2 p}{3} + 27 = 39$

Step 2

Move all terms not containing $p$ to the right side of the equation.

Subtract $27$ from both sides of the equation.

$\frac{2 p}{3} = 39 - 27$

Subtract $27$ from $39$ .

$\frac{2 p}{3} = 12$

Step 3

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} \cdot \frac{2 p}{3} = \frac{3}{2} \cdot 12$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{2} \cdot \frac{2 p}{3}$ .

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 p}{3} = \frac{3}{2} \cdot 12$

Rewrite the expression.

$\frac{1}{2} (2 p) = \frac{3}{2} \cdot 12$

Cancel the common factor of $2$ .

Factor $2$ out of $2 p$ .

$\frac{1}{2} (2 (p)) = \frac{3}{2} \cdot 12$

Cancel the common factor.

$\frac{1}{2} (2 p) = \frac{3}{2} \cdot 12$

Rewrite the expression.

$p = \frac{3}{2} \cdot 12$

Simplify the right side.

Simplify $\frac{3}{2} \cdot 12$ .

Cancel the common factor of $2$ .

Factor $2$ out of $12$ .

$p = \frac{3}{2} \cdot (2 (6))$

Cancel the common factor.

$p = \frac{3}{2} \cdot (2 \cdot 6)$

Rewrite the expression.

$p = 3 \cdot 6$

Multiply $3$ by $6$ .

$p = 18$

Solve for p (4p)/6+27=39

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