Solve for p 6-4(3p-2)=6(1-2p)-1

$6 - 4 (3 p - 2) = 6 (1 - 2 p) - 1$

Step 1

Simplify $6 - 4 (3 p - 2)$ .

Simplify each term.

Apply the distributive property.

$6 - 4 (3 p) - 4 \cdot - 2 = 6 (1 - 2 p) - 1$

Multiply $3$ by $- 4$ .

$6 - 12 p - 4 \cdot - 2 = 6 (1 - 2 p) - 1$

Multiply $- 4$ by $- 2$ .

$6 - 12 p + 8 = 6 (1 - 2 p) - 1$

Add $6$ and $8$ .

$- 12 p + 14 = 6 (1 - 2 p) - 1$

Step 2

Simplify $6 (1 - 2 p) - 1$ .

Simplify each term.

Apply the distributive property.

$- 12 p + 14 = 6 \cdot 1 + 6 (- 2 p) - 1$

Multiply $6$ by $1$ .

$- 12 p + 14 = 6 + 6 (- 2 p) - 1$

Multiply $- 2$ by $6$ .

$- 12 p + 14 = 6 - 12 p - 1$

Subtract $1$ from $6$ .

$- 12 p + 14 = - 12 p + 5$

Step 3

Move all terms containing $p$ to the left side of the equation.

Add $12 p$ to both sides of the equation.

$- 12 p + 14 + 12 p = 5$

Combine the opposite terms in $- 12 p + 14 + 12 p$ .

Add $- 12 p$ and $12 p$ .

$0 + 14 = 5$

Add $0$ and $14$ .

$14 = 5$

Step 4

Since $14 \neq 5$ , there are no solutions.

No solution