Solve for p 7p-(3p+4)=-2(2p-1)+10

$7 p - (3 p + 4) = - 2 (2 p - 1) + 10$

Simplify $7 p - (3 p + 4)$ .

Simplify each term.

Apply the distributive property.

$7 p - (3 p) - 1 \cdot 4 = - 2 (2 p - 1) + 10$

Multiply $3$ by $- 1$ .

$7 p - 3 p - 1 \cdot 4 = - 2 (2 p - 1) + 10$

Multiply $- 1$ by $4$ .

$7 p - 3 p - 4 = - 2 (2 p - 1) + 10$

Subtract $3 p$ from $7 p$ .

$4 p - 4 = - 2 (2 p - 1) + 10$

Simplify $- 2 (2 p - 1) + 10$ .

Simplify each term.

Apply the distributive property.

$4 p - 4 = - 2 (2 p) - 2 \cdot - 1 + 10$

Multiply $2$ by $- 2$ .

$4 p - 4 = - 4 p - 2 \cdot - 1 + 10$

Multiply $- 2$ by $- 1$ .

$4 p - 4 = - 4 p + 2 + 10$

Add $2$ and $10$ .

$4 p - 4 = - 4 p + 12$

Move all terms containing $p$ to the left side of the equation.

Add $4 p$ to both sides of the equation.

$4 p - 4 + 4 p = 12$

Add $4 p$ and $4 p$ .

$8 p - 4 = 12$

Move all terms not containing $p$ to the right side of the equation.

Add $4$ to both sides of the equation.

$8 p = 12 + 4$

Add $12$ and $4$ .

$8 p = 16$

Divide each term in $8 p = 16$ by $8$ and simplify.

Divide each term in $8 p = 16$ by $8$ .

$\frac{8 p}{8} = \frac{16}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 p}{8} = \frac{16}{8}$

Divide $p$ by $1$ .

$p = \frac{16}{8}$

Simplify the right side.

Divide $16$ by $8$ .

$p = 2$