Solve for p -9(2p+1)=-15p

$- 9 (2 p + 1) = - 15 p$

Simplify $- 9 (2 p + 1)$ .

Start simplifying.

$0 + 0 - 9 (2 p + 1) = - 15 p$

Simplify by adding zeros.

$- 9 (2 p + 1) = - 15 p$

Apply the distributive property.

$- 9 (2 p) - 9 \cdot 1 = - 15 p$

Multiply.

Multiply $2$ by $- 9$ .

$- 18 p - 9 \cdot 1 = - 15 p$

Multiply $- 9$ by $1$ .

$- 18 p - 9 = - 15 p$

Move all terms containing $p$ to the left side of the equation.

Add $15 p$ to both sides of the equation.

$- 18 p - 9 + 15 p = 0$

Add $- 18 p$ and $15 p$ .

$- 3 p - 9 = 0$

Add $9$ to both sides of the equation.

$- 3 p = 9$

Divide each term in $- 3 p = 9$ by $- 3$ and simplify.

Divide each term in $- 3 p = 9$ by $- 3$ .

$\frac{- 3 p}{- 3} = \frac{9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 p}{- 3} = \frac{9}{- 3}$

Divide $p$ by $1$ .

$p = \frac{9}{- 3}$

Simplify the right side.

Divide $9$ by $- 3$ .

$p = - 3$