Solve for p 9-4(2p-1)=45

$9 - 4 (2 p - 1) = 45$

Step 1

Simplify $9 - 4 (2 p - 1)$ .

Simplify each term.

Apply the distributive property.

$9 - 4 (2 p) - 4 \cdot - 1 = 45$

Multiply $2$ by $- 4$ .

$9 - 8 p - 4 \cdot - 1 = 45$

Multiply $- 4$ by $- 1$ .

$9 - 8 p + 4 = 45$

Add $9$ and $4$ .

$- 8 p + 13 = 45$

Step 2

Move all terms not containing $p$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 8 p = 45 - 13$

Subtract $13$ from $45$ .

$- 8 p = 32$

Step 3

Divide each term in $- 8 p = 32$ by $- 8$ and simplify.

Divide each term in $- 8 p = 32$ by $- 8$ .

$\frac{- 8 p}{- 8} = \frac{32}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 p}{- 8} = \frac{32}{- 8}$

Divide $p$ by $1$ .

$p = \frac{32}{- 8}$

Simplify the right side.

Divide $32$ by $- 8$ .

$p = - 4$