Solve for p log of 4p-2 = log of -5p+5

$\log (4 p - 2) = \log (- 5 p + 5)$

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

$4 p - 2 = - 5 p + 5$

Solve for $p$ .

Move all terms containing $p$ to the left side of the equation.

Add $5 p$ to both sides of the equation.

$4 p - 2 + 5 p = 5$

Add $4 p$ and $5 p$ .

$9 p - 2 = 5$

Move all terms not containing $p$ to the right side of the equation.

Add $2$ to both sides of the equation.

$9 p = 5 + 2$

Add $5$ and $2$ .

$9 p = 7$

Divide each term in $9 p = 7$ by $9$ and simplify.

Divide each term in $9 p = 7$ by $9$ .

$\frac{9 p}{9} = \frac{7}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 p}{9} = \frac{7}{9}$

Divide $p$ by $1$ .

$p = \frac{7}{9}$

The result can be shown in multiple forms.

Exact Form:

$p = \frac{7}{9}$

Decimal Form:

$p = 0.\overline{7}$