Solve for p s=ph+2b

$s = p h + 2 b$

Rewrite the equation as $p h + 2 b = s$ .

$p h + 2 b = s$

Subtract $2 b$ from both sides of the equation.

$p h = s - 2 b$

Divide each term in $p h = s - 2 b$ by $h$ and simplify.

Divide each term in $p h = s - 2 b$ by $h$ .

$\frac{p h}{h} = \frac{s}{h} + \frac{- 2 b}{h}$

Simplify the left side.

Cancel the common factor of $h$ .

Cancel the common factor.

$\frac{p h}{h} = \frac{s}{h} + \frac{- 2 b}{h}$

Divide $p$ by $1$ .

$p = \frac{s}{h} + \frac{- 2 b}{h}$

Simplify the right side.

Move the negative in front of the fraction.

$p = \frac{s}{h} - \frac{2 b}{h}$