Solve for q 10q-3r=14

$10 q - 3 r = 14$

Add $3 r$ to both sides of the equation.

$10 q = 14 + 3 r$

Divide each term in $10 q = 14 + 3 r$ by $10$ and simplify.

Divide each term in $10 q = 14 + 3 r$ by $10$ .

$\frac{10 q}{10} = \frac{14}{10} + \frac{3 r}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 q}{10} = \frac{14}{10} + \frac{3 r}{10}$

Divide $q$ by $1$ .

$q = \frac{14}{10} + \frac{3 r}{10}$

Simplify the right side.

Cancel the common factor of $14$ and $10$ .

Factor $2$ out of $14$ .

$q = \frac{2 (7)}{10} + \frac{3 r}{10}$

Cancel the common factors.

Factor $2$ out of $10$ .

$q = \frac{2 \cdot 7}{2 \cdot 5} + \frac{3 r}{10}$

Cancel the common factor.

$q = \frac{2 \cdot 7}{2 \cdot 5} + \frac{3 r}{10}$

Rewrite the expression.

$q = \frac{7}{5} + \frac{3 r}{10}$