Solve for q 4(3q+10)=6(2q-9)

$4 (3 q + 10) = 6 (2 q - 9)$

Simplify $4 (3 q + 10)$ .

Start simplifying.

$0 + 0 + 4 (3 q + 10) = 6 (2 q - 9)$

Simplify by adding zeros.

$4 (3 q + 10) = 6 (2 q - 9)$

Apply the distributive property.

$4 (3 q) + 4 \cdot 10 = 6 (2 q - 9)$

Multiply.

Multiply $3$ by $4$ .

$12 q + 4 \cdot 10 = 6 (2 q - 9)$

Multiply $4$ by $10$ .

$12 q + 40 = 6 (2 q - 9)$

Simplify $6 (2 q - 9)$ .

Apply the distributive property.

$12 q + 40 = 6 (2 q) + 6 \cdot - 9$

Multiply.

Multiply $2$ by $6$ .

$12 q + 40 = 12 q + 6 \cdot - 9$

Multiply $6$ by $- 9$ .

$12 q + 40 = 12 q - 54$

Move all terms containing $q$ to the left side of the equation.

Subtract $12 q$ from both sides of the equation.

$12 q + 40 - 12 q = - 54$

Combine the opposite terms in $12 q + 40 - 12 q$ .

Subtract $12 q$ from $12 q$ .

$0 + 40 = - 54$

Add $0$ and $40$ .

$40 = - 54$

Since $40 \neq - 54$ , there are no solutions.

No solution