Solve for q 8q+12=4(3+2q)

$8 q + 12 = 4 (3 + 2 q)$

Simplify $4 (3 + 2 q)$ .

Rewrite.

$8 q + 12 = 0 + 0 + 4 (3 + 2 q)$

Simplify by adding zeros.

$8 q + 12 = 4 (3 + 2 q)$

Apply the distributive property.

$8 q + 12 = 4 \cdot 3 + 4 (2 q)$

Multiply.

Multiply $4$ by $3$ .

$8 q + 12 = 12 + 4 (2 q)$

Multiply $2$ by $4$ .

$8 q + 12 = 12 + 8 q$

Move all terms containing $q$ to the left side of the equation.

Subtract $8 q$ from both sides of the equation.

$8 q + 12 - 8 q = 12$

Combine the opposite terms in $8 q + 12 - 8 q$ .

Subtract $8 q$ from $8 q$ .

$0 + 12 = 12$

Add $0$ and $12$ .

$12 = 12$

Since $12 = 12$ , the equation will always be true for any value of $q$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$