Solve for q 8q=18-2p

$8 q = 18 - 2 p$

Divide each term in $8 q = 18 - 2 p$ by $8$ .

$\frac{8 q}{8} = \frac{18}{8} + \frac{- 2 p}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 q}{8} = \frac{18}{8} + \frac{- 2 p}{8}$

Divide $q$ by $1$ .

$q = \frac{18}{8} + \frac{- 2 p}{8}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $18$ and $8$ .

Factor $2$ out of $18$ .

$q = \frac{2 (9)}{8} + \frac{- 2 p}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$q = \frac{2 \cdot 9}{2 \cdot 4} + \frac{- 2 p}{8}$

Cancel the common factor.

$q = \frac{2 \cdot 9}{2 \cdot 4} + \frac{- 2 p}{8}$

Rewrite the expression.

$q = \frac{9}{4} + \frac{- 2 p}{8}$

Cancel the common factor of $- 2$ and $8$ .

Factor $2$ out of $- 2 p$ .

$q = \frac{9}{4} + \frac{2 (- p)}{8}$

Cancel the common factors.

Factor $2$ out of $8$ .

$q = \frac{9}{4} + \frac{2 (- p)}{2 (4)}$

Cancel the common factor.

$q = \frac{9}{4} + \frac{2 (- p)}{2 \cdot 4}$

Rewrite the expression.

$q = \frac{9}{4} + \frac{- p}{4}$

Move the negative in front of the fraction.

$q = \frac{9}{4} - \frac{p}{4}$