Solve for q 8q-8=-4(-5q-10)

$8 q - 8 = - 4 (- 5 q - 10)$

Step 1

Simplify $- 4 (- 5 q - 10)$ .

Rewrite.

$8 q - 8 = 0 + 0 - 4 (- 5 q - 10)$

Simplify by adding zeros.

$8 q - 8 = - 4 (- 5 q - 10)$

Apply the distributive property.

$8 q - 8 = - 4 (- 5 q) - 4 \cdot - 10$

Multiply.

Multiply $- 5$ by $- 4$ .

$8 q - 8 = 20 q - 4 \cdot - 10$

Multiply $- 4$ by $- 10$ .

$8 q - 8 = 20 q + 40$

Step 2

Move all terms containing $q$ to the left side of the equation.

Subtract $20 q$ from both sides of the equation.

$8 q - 8 - 20 q = 40$

Subtract $20 q$ from $8 q$ .

$- 12 q - 8 = 40$

Step 3

Move all terms not containing $q$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- 12 q = 40 + 8$

Add $40$ and $8$ .

$- 12 q = 48$

Step 4

Divide each term in $- 12 q = 48$ by $- 12$ and simplify.

Divide each term in $- 12 q = 48$ by $- 12$ .

$\frac{- 12 q}{- 12} = \frac{48}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 q}{- 12} = \frac{48}{- 12}$

Divide $q$ by $1$ .

$q = \frac{48}{- 12}$

Simplify the right side.

Divide $48$ by $- 12$ .

$q = - 4$