Solve for q qx+56=-28x+p

$q x + 56 = - 28 x + p$

Subtract $56$ from both sides of the equation.

$q x = - 28 x + p - 56$

Divide each term in $q x = - 28 x + p - 56$ by $x$ and simplify.

Divide each term in $q x = - 28 x + p - 56$ by $x$ .

$\frac{q x}{x} = \frac{- 28 x}{x} + \frac{p}{x} + \frac{- 56}{x}$

Simplify the left side.

Cancel the common factor of $x$ .

Cancel the common factor.

$\frac{q x}{x} = \frac{- 28 x}{x} + \frac{p}{x} + \frac{- 56}{x}$

Divide $q$ by $1$ .

$q = \frac{- 28 x}{x} + \frac{p}{x} + \frac{- 56}{x}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $x$ .

Cancel the common factor.

$q = \frac{- 28 x}{x} + \frac{p}{x} + \frac{- 56}{x}$

Divide $- 28$ by $1$ .

$q = - 28 + \frac{p}{x} + \frac{- 56}{x}$

Move the negative in front of the fraction.

$q = - 28 + \frac{p}{x} - \frac{56}{x}$