Solve for q r=6n+2q

$r = 6 n + 2 q$

Step 1

Rewrite the equation as $6 n + 2 q = r$ .

$6 n + 2 q = r$

Step 2

Subtract $6 n$ from both sides of the equation.

$2 q = r - 6 n$

Step 3

Divide each term in $2 q = r - 6 n$ by $2$ and simplify.

Divide each term in $2 q = r - 6 n$ by $2$ .

$\frac{2 q}{2} = \frac{r}{2} + \frac{- 6 n}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 q}{2} = \frac{r}{2} + \frac{- 6 n}{2}$

Divide $q$ by $1$ .

$q = \frac{r}{2} + \frac{- 6 n}{2}$

$q = \frac{r}{2} + \frac{- 6 n}{2}$

$q = \frac{r}{2} + \frac{- 6 n}{2}$

Simplify the right side.

Cancel the common factor of $- 6$ and $2$ .

Factor $2$ out of $- 6 n$ .

$q = \frac{r}{2} + \frac{2 (- 3 n)}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$q = \frac{r}{2} + \frac{2 (- 3 n)}{2 (1)}$

Cancel the common factor.

$q = \frac{r}{2} + \frac{2 (- 3 n)}{2 \cdot 1}$

Rewrite the expression.

$q = \frac{r}{2} + \frac{- 3 n}{1}$

Divide $- 3 n$ by $1$ .

$q = \frac{r}{2} - 3 n$

$q = \frac{r}{2} - 3 n$

$q = \frac{r}{2} - 3 n$

$q = \frac{r}{2} - 3 n$

$q = \frac{r}{2} - 3 n$

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