Solve for r -18=5/2r+12

$- 18 = \frac{5}{2} r + 12$

Rewrite the equation as $\frac{5}{2} r + 12 = - 18$ .

$\frac{5}{2} r + 12 = - 18$

Combine $\frac{5}{2}$ and $r$ .

$\frac{5 r}{2} + 12 = - 18$

Move all terms not containing $r$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$\frac{5 r}{2} = - 18 - 12$

Subtract $12$ from $- 18$ .

$\frac{5 r}{2} = - 30$

Multiply both sides of the equation by $\frac{2}{5}$ .

$\frac{2}{5} \cdot \frac{5 r}{2} = \frac{2}{5} \cdot - 30$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{2}{5} \cdot \frac{5 r}{2}$ .

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2}{5} \cdot \frac{5 r}{2} = \frac{2}{5} \cdot - 30$

Rewrite the expression.

$\frac{1}{5} (5 r) = \frac{2}{5} \cdot - 30$

Cancel the common factor of $5$ .

Factor $5$ out of $5 r$ .

$\frac{1}{5} (5 (r)) = \frac{2}{5} \cdot - 30$

Cancel the common factor.

$\frac{1}{5} (5 r) = \frac{2}{5} \cdot - 30$

Rewrite the expression.

$r = \frac{2}{5} \cdot - 30$

Simplify the right side.

Simplify $\frac{2}{5} \cdot - 30$ .

Cancel the common factor of $5$ .

Factor $5$ out of $- 30$ .

$r = \frac{2}{5} \cdot (5 (- 6))$

Cancel the common factor.

$r = \frac{2}{5} \cdot (5 \cdot - 6)$

Rewrite the expression.

$r = 2 \cdot - 6$

Multiply $2$ by $- 6$ .

$r = - 12$