Solve for r 2/3+r=-4/9

$\frac{2}{3} + r = - \frac{4}{9}$

Subtract $\frac{2}{3}$ from both sides of the equation.

$r = - \frac{4}{9} - \frac{2}{3}$

To write $- \frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$r = - \frac{4}{9} - \frac{2}{3} \cdot \frac{3}{3}$

Write each expression with a common denominator of $9$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2}{3}$ by $\frac{3}{3}$ .

$r = - \frac{4}{9} - \frac{2 \cdot 3}{3 \cdot 3}$

Multiply $3$ by $3$ .

$r = - \frac{4}{9} - \frac{2 \cdot 3}{9}$

Combine the numerators over the common denominator.

$r = \frac{- 4 - 2 \cdot 3}{9}$

Simplify the numerator.

Multiply $- 2$ by $3$ .

$r = \frac{- 4 - 6}{9}$

Subtract $6$ from $- 4$ .

$r = \frac{- 10}{9}$

Move the negative in front of the fraction.

$r = - \frac{10}{9}$

The result can be shown in multiple forms.

Exact Form:

$r = - \frac{10}{9}$

Decimal Form:

$r = - 1.\overline{1}$

Mixed Number Form:

$r = - 1 \frac{1}{9}$