Solve for r 25+r=-5(2+8r)+6r

$25 + r = - 5 (2 + 8 r) + 6 r$

Since $r$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- 5 (2 + 8 r) + 6 r = 25 + r$

Simplify $- 5 (2 + 8 r) + 6 r$ .

Simplify each term.

Apply the distributive property.

$- 5 \cdot 2 - 5 (8 r) + 6 r = 25 + r$

Multiply $- 5$ by $2$ .

$- 10 - 5 (8 r) + 6 r = 25 + r$

Multiply $8$ by $- 5$ .

$- 10 - 40 r + 6 r = 25 + r$

Add $- 40 r$ and $6 r$ .

$- 10 - 34 r = 25 + r$

Move all terms containing $r$ to the left side of the equation.

Subtract $r$ from both sides of the equation.

$- 10 - 34 r - r = 25$

Subtract $r$ from $- 34 r$ .

$- 10 - 35 r = 25$

Move all terms not containing $r$ to the right side of the equation.

Add $10$ to both sides of the equation.

$- 35 r = 25 + 10$

Add $25$ and $10$ .

$- 35 r = 35$

Divide each term in $- 35 r = 35$ by $- 35$ and simplify.

Divide each term in $- 35 r = 35$ by $- 35$ .

$\frac{- 35 r}{- 35} = \frac{35}{- 35}$

Simplify the left side.

Cancel the common factor of $- 35$ .

Cancel the common factor.

$\frac{- 35 r}{- 35} = \frac{35}{- 35}$

Divide $r$ by $1$ .

$r = \frac{35}{- 35}$

Simplify the right side.

Divide $35$ by $- 35$ .

$r = - 1$