Solve for r -3(r-4)=0

$- 3 (r - 4) = 0$

Step 1

Divide each term in $- 3 (r - 4) = 0$ by $- 3$ and simplify.

Divide each term in $- 3 (r - 4) = 0$ by $- 3$ .

$\frac{- 3 (r - 4)}{- 3} = \frac{0}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (r - 4)}{- 3} = \frac{0}{- 3}$

Divide $r - 4$ by $1$ .

$r - 4 = \frac{0}{- 3}$

Simplify the right side.

Divide $0$ by $- 3$ .

$r - 4 = 0$

Step 2

Add $4$ to both sides of the equation.

$r = 4$