Solve for r (3r+4)/2=5

$\frac{3 r + 4}{2} = 5$

Multiply both sides by $2$ .

$\frac{3 r + 4}{2} \cdot 2 = 5 \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{3 r + 4}{2} \cdot 2 = 5 \cdot 2$

Rewrite the expression.

$3 r + 4 = 5 \cdot 2$

Simplify the right side.

Multiply $5$ by $2$ .

$3 r + 4 = 10$

Solve for $r$ .

Move all terms not containing $r$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$3 r = 10 - 4$

Subtract $4$ from $10$ .

$3 r = 6$

Divide each term in $3 r = 6$ by $3$ and simplify.

Divide each term in $3 r = 6$ by $3$ .

$\frac{3 r}{3} = \frac{6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 r}{3} = \frac{6}{3}$

Divide $r$ by $1$ .

$r = \frac{6}{3}$

Simplify the right side.

Divide $6$ by $3$ .

$r = 2$