Solve for r 4(2r-1)=-2(3r+16)

$4 (2 r - 1) = - 2 (3 r + 16)$

Step 1

Simplify $4 (2 r - 1)$ .

Start simplifying.

$0 + 0 + 4 (2 r - 1) = - 2 (3 r + 16)$

Simplify by adding zeros.

$4 (2 r - 1) = - 2 (3 r + 16)$

Apply the distributive property.

$4 (2 r) + 4 \cdot - 1 = - 2 (3 r + 16)$

Multiply.

Multiply $2$ by $4$ .

$8 r + 4 \cdot - 1 = - 2 (3 r + 16)$

Multiply $4$ by $- 1$ .

$8 r - 4 = - 2 (3 r + 16)$

Step 2

Simplify $- 2 (3 r + 16)$ .

Apply the distributive property.

$8 r - 4 = - 2 (3 r) - 2 \cdot 16$

Multiply.

Multiply $3$ by $- 2$ .

$8 r - 4 = - 6 r - 2 \cdot 16$

Multiply $- 2$ by $16$ .

$8 r - 4 = - 6 r - 32$

Step 3

Move all terms containing $r$ to the left side of the equation.

Add $6 r$ to both sides of the equation.

$8 r - 4 + 6 r = - 32$

Add $8 r$ and $6 r$ .

$14 r - 4 = - 32$

Step 4

Move all terms not containing $r$ to the right side of the equation.

Add $4$ to both sides of the equation.

$14 r = - 32 + 4$

Add $- 32$ and $4$ .

$14 r = - 28$

Step 5

Divide each term in $14 r = - 28$ by $14$ and simplify.

Divide each term in $14 r = - 28$ by $14$ .

$\frac{14 r}{14} = \frac{- 28}{14}$

Simplify the left side.

Cancel the common factor of $14$ .

Cancel the common factor.

$\frac{14 r}{14} = \frac{- 28}{14}$

Divide $r$ by $1$ .

$r = \frac{- 28}{14}$

Simplify the right side.

Divide $- 28$ by $14$ .

$r = - 2$

Solve for r 4(2r-1)=-2(3r+16)

Related Questions

Support LCMGCF.com by disabling your adblocker.