Solve for r -4/3r=-7

$- \frac{4}{3} r = - 7$

Multiply both sides of the equation by $- \frac{3}{4}$ .

$- \frac{3}{4} (- \frac{4}{3} r) = - \frac{3}{4} \cdot - 7$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{4} (- \frac{4}{3} r)$ .

Combine $r$ and $\frac{4}{3}$ .

$- \frac{3}{4} (- \frac{r \cdot 4}{3}) = - \frac{3}{4} \cdot - 7$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{4}$ into the numerator.

$\frac{- 3}{4} (- \frac{r \cdot 4}{3}) = - \frac{3}{4} \cdot - 7$

Move the leading negative in $- \frac{r \cdot 4}{3}$ into the numerator.

$\frac{- 3}{4} \cdot \frac{- r \cdot 4}{3} = - \frac{3}{4} \cdot - 7$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{4} \cdot \frac{- r \cdot 4}{3} = - \frac{3}{4} \cdot - 7$

Cancel the common factor.

$\frac{3 \cdot - 1}{4} \cdot \frac{- r \cdot 4}{3} = - \frac{3}{4} \cdot - 7$

Rewrite the expression.

$\frac{- 1}{4} (- r \cdot 4) = - \frac{3}{4} \cdot - 7$

Cancel the common factor of $4$ .

Factor $4$ out of $- r \cdot 4$ .

$\frac{- 1}{4} (4 \cdot (- r)) = - \frac{3}{4} \cdot - 7$

Cancel the common factor.

$\frac{- 1}{4} (4 \cdot (- r)) = - \frac{3}{4} \cdot - 7$

Rewrite the expression.

$- - r = - \frac{3}{4} \cdot - 7$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 r = - \frac{3}{4} \cdot - 7$

Multiply $r$ by $1$ .

$r = - \frac{3}{4} \cdot - 7$

Simplify the right side.

Multiply $- \frac{3}{4} \cdot - 7$ .

Multiply $- 7$ by $- 1$ .

$r = 7 (\frac{3}{4})$

Combine $7$ and $\frac{3}{4}$ .

$r = \frac{7 \cdot 3}{4}$

Multiply $7$ by $3$ .

$r = \frac{21}{4}$

The result can be shown in multiple forms.

Exact Form:

$r = \frac{21}{4}$

Decimal Form:

$r = 5.25$

Mixed Number Form:

$r = 5 \frac{1}{4}$

Solve for r -4/3r=-7

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