Solve for r 4(p+8)=2(r-6)

$4 (p + 8) = 2 (r - 6)$

Step 1

Rewrite the equation as $2 (r - 6) = 4 (p + 8)$ .

$2 (r - 6) = 4 (p + 8)$

Step 2

Divide each term in $2 (r - 6) = 4 (p + 8)$ by $2$ and simplify.

Divide each term in $2 (r - 6) = 4 (p + 8)$ by $2$ .

$\frac{2 (r - 6)}{2} = \frac{4 (p + 8)}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (r - 6)}{2} = \frac{4 (p + 8)}{2}$

Divide $r - 6$ by $1$ .

$r - 6 = \frac{4 (p + 8)}{2}$

Simplify the right side.

Cancel the common factor of $4$ and $2$ .

Factor $2$ out of $4 (p + 8)$ .

$r - 6 = \frac{2 (2 (p + 8))}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$r - 6 = \frac{2 (2 (p + 8))}{2 (1)}$

Cancel the common factor.

$r - 6 = \frac{2 (2 (p + 8))}{2 \cdot 1}$

Rewrite the expression.

$r - 6 = \frac{2 (p + 8)}{1}$

Divide $2 (p + 8)$ by $1$ .

$r - 6 = 2 (p + 8)$

Apply the distributive property.

$r - 6 = 2 p + 2 \cdot 8$

Multiply $2$ by $8$ .

$r - 6 = 2 p + 16$

Step 3

Move all terms not containing $r$ to the right side of the equation.

Add $6$ to both sides of the equation.

$r = 2 p + 16 + 6$

Add $16$ and $6$ .

$r = 2 p + 22$