Solve for r 5(x-4)+4+r=4(x+3)+x

$5 (x - 4) + 4 + r = 4 (x + 3) + x$

Simplify $5 (x - 4) + 4 + r$ .

Simplify each term.

Apply the distributive property.

$5 x + 5 \cdot - 4 + 4 + r = 4 (x + 3) + x$

Multiply $5$ by $- 4$ .

$5 x - 20 + 4 + r = 4 (x + 3) + x$

Add $- 20$ and $4$ .

$5 x - 16 + r = 4 (x + 3) + x$

Simplify $4 (x + 3) + x$ .

Simplify each term.

Apply the distributive property.

$5 x - 16 + r = 4 x + 4 \cdot 3 + x$

Multiply $4$ by $3$ .

$5 x - 16 + r = 4 x + 12 + x$

Add $4 x$ and $x$ .

$5 x - 16 + r = 5 x + 12$

Move all terms not containing $r$ to the right side of the equation.

Subtract $5 x$ from both sides of the equation.

$- 16 + r = 5 x + 12 - 5 x$

Add $16$ to both sides of the equation.

$r = 5 x + 12 - 5 x + 16$

Combine the opposite terms in $5 x + 12 - 5 x + 16$ .

Subtract $5 x$ from $5 x$ .

$r = 0 + 12 + 16$

Add $0$ and $12$ .

$r = 12 + 16$

Add $12$ and $16$ .

$r = 28$