Solve for r 6r+7=13+7r

$6 r + 7 = 13 + 7 r$

Step 1

Move all terms containing $r$ to the left side of the equation.

Subtract $7 r$ from both sides of the equation.

$6 r + 7 - 7 r = 13$

Subtract $7 r$ from $6 r$ .

$- r + 7 = 13$

Step 2

Move all terms not containing $r$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- r = 13 - 7$

Subtract $7$ from $13$ .

$- r = 6$

Step 3

Divide each term in $- r = 6$ by $- 1$ and simplify.

Divide each term in $- r = 6$ by $- 1$ .

$\frac{- r}{- 1} = \frac{6}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{r}{1} = \frac{6}{- 1}$

Divide $r$ by $1$ .

$r = \frac{6}{- 1}$

Simplify the right side.

Divide $6$ by $- 1$ .

$r = - 6$