Solve for r e^(r+10)-10=-42

$e^{r + 10} - 10 = - 42$

Move all terms not containing $r$ to the right side of the equation.

Add $10$ to both sides of the equation.

$e^{r + 10} = - 42 + 10$

Add $- 42$ and $10$ .

$e^{r + 10} = - 32$

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{r + 10}) = \ln (- 32)$

The equation cannot be solved because $\ln (- 32)$ is undefined.

Undefined

There is no solution for $e^{r + 10} = - 32$

No solution