Solve for r (r-3)(r+6)=0

$(r - 3) (r + 6) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$r - 3 = 0$

$r + 6 = 0$

Set $r - 3$ equal to $0$ and solve for $r$ .

Set $r - 3$ equal to $0$ .

$r - 3 = 0$

Add $3$ to both sides of the equation.

$r = 3$

Set $r + 6$ equal to $0$ and solve for $r$ .

Set $r + 6$ equal to $0$ .

$r + 6 = 0$

Subtract $6$ from both sides of the equation.

$r = - 6$

The final solution is all the values that make $(r - 3) (r + 6) = 0$ true.

$r = 3, - 6$