Solve for r r-rs=2rs+5

$r - r s = 2 r s + 5$

Move all terms containing $r$ to the left side of the equation.

Subtract $2 r s$ from both sides of the equation.

$r - r s - 2 r s = 5$

Subtract $2 r s$ from $- r s$ .

$r - 3 r s = 5$

Factor $r$ out of $r - 3 r s$ .

Factor $r$ out of $r^{1}$ .

$r \cdot 1 - 3 r s = 5$

Factor $r$ out of $- 3 r s$ .

$r \cdot 1 + r (- 3 s) = 5$

Factor $r$ out of $r \cdot 1 + r (- 3 s)$ .

$r (1 - 3 s) = 5$

Divide each term in $r (1 - 3 s) = 5$ by $1 - 3 s$ and simplify.

Divide each term in $r (1 - 3 s) = 5$ by $1 - 3 s$ .

$\frac{r (1 - 3 s)}{1 - 3 s} = \frac{5}{1 - 3 s}$

Simplify the left side.

Cancel the common factor of $1 - 3 s$ .

Cancel the common factor.

$\frac{r (1 - 3 s)}{1 - 3 s} = \frac{5}{1 - 3 s}$

Divide $r$ by $1$ .

$r = \frac{5}{1 - 3 s}$