Solve for s -15r+9s=-6

$- 15 r + 9 s = - 6$

Add $15 r$ to both sides of the equation.

$9 s = - 6 + 15 r$

Divide each term in $9 s = - 6 + 15 r$ by $9$ and simplify.

Divide each term in $9 s = - 6 + 15 r$ by $9$ .

$\frac{9 s}{9} = \frac{- 6}{9} + \frac{15 r}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 s}{9} = \frac{- 6}{9} + \frac{15 r}{9}$

Divide $s$ by $1$ .

$s = \frac{- 6}{9} + \frac{15 r}{9}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 6$ and $9$ .

Factor $3$ out of $- 6$ .

$s = \frac{3 (- 2)}{9} + \frac{15 r}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$s = \frac{3 \cdot - 2}{3 \cdot 3} + \frac{15 r}{9}$

Cancel the common factor.

$s = \frac{3 \cdot - 2}{3 \cdot 3} + \frac{15 r}{9}$

Rewrite the expression.

$s = \frac{- 2}{3} + \frac{15 r}{9}$

Move the negative in front of the fraction.

$s = - \frac{2}{3} + \frac{15 r}{9}$

Cancel the common factor of $15$ and $9$ .

Factor $3$ out of $15 r$ .

$s = - \frac{2}{3} + \frac{3 (5 r)}{9}$

Cancel the common factors.

Factor $3$ out of $9$ .

$s = - \frac{2}{3} + \frac{3 (5 r)}{3 (3)}$

Cancel the common factor.

$s = - \frac{2}{3} + \frac{3 (5 r)}{3 \cdot 3}$

Rewrite the expression.

$s = - \frac{2}{3} + \frac{5 r}{3}$