Solve for s -4(3s-2)=-6(2s-1)-2

$- 4 (3 s - 2) = - 6 (2 s - 1) - 2$

Step 1

Simplify $- 4 (3 s - 2)$ .

Rewrite.

$0 + 0 - 4 (3 s - 2) = - 6 (2 s - 1) - 2$

Simplify by adding zeros.

$- 4 (3 s - 2) = - 6 (2 s - 1) - 2$

Apply the distributive property.

$- 4 (3 s) - 4 \cdot - 2 = - 6 (2 s - 1) - 2$

Multiply.

Multiply $3$ by $- 4$ .

$- 12 s - 4 \cdot - 2 = - 6 (2 s - 1) - 2$

Multiply $- 4$ by $- 2$ .

$- 12 s + 8 = - 6 (2 s - 1) - 2$

Step 2

Simplify $- 6 (2 s - 1) - 2$ .

Simplify each term.

Apply the distributive property.

$- 12 s + 8 = - 6 (2 s) - 6 \cdot - 1 - 2$

Multiply $2$ by $- 6$ .

$- 12 s + 8 = - 12 s - 6 \cdot - 1 - 2$

Multiply $- 6$ by $- 1$ .

$- 12 s + 8 = - 12 s + 6 - 2$

Subtract $2$ from $6$ .

$- 12 s + 8 = - 12 s + 4$

Step 3

Move all terms containing $s$ to the left side of the equation.

Add $12 s$ to both sides of the equation.

$- 12 s + 8 + 12 s = 4$

Combine the opposite terms in $- 12 s + 8 + 12 s$ .

Add $- 12 s$ and $12 s$ .

$0 + 8 = 4$

Add $0$ and $8$ .

$8 = 4$

Step 4

Since $8 \neq 4$ , there are no solutions.

No solution