Solve for s 5-4s=4(5-st)

$5 - 4 s = 4 (5 - s t)$

Step 1

Simplify $4 (5 - s t)$ .

Rewrite.

$5 - 4 s = 0 + 0 + 4 (5 - s t)$

Simplify by adding zeros.

$5 - 4 s = 4 (5 - s t)$

Apply the distributive property.

$5 - 4 s = 4 \cdot 5 + 4 (- s t)$

Multiply.

Multiply $4$ by $5$ .

$5 - 4 s = 20 + 4 (- s t)$

Multiply $- 1$ by $4$ .

$5 - 4 s = 20 - 4 s t$

Step 2

Add $4 s t$ to both sides of the equation.

$5 - 4 s + 4 s t = 20$

Step 3

Move all terms not containing $s$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- 4 s + 4 s t = 20 - 5$

Subtract $5$ from $20$ .

$- 4 s + 4 s t = 15$

Step 4

Factor $4 s$ out of $- 4 s + 4 s t$ .

Factor $4 s$ out of $- 4 s$ .

$4 s (- 1) + 4 s t = 15$

Factor $4 s$ out of $4 s t$ .

$4 s (- 1) + 4 s (t) = 15$

Factor $4 s$ out of $4 s (- 1) + 4 s (t)$ .

$4 s (- 1 + t) = 15$

Step 5

Divide each term in $4 s (- 1 + t) = 15$ by $4 (- 1 + t)$ and simplify.

Divide each term in $4 s (- 1 + t) = 15$ by $4 (- 1 + t)$ .

$\frac{4 s (- 1 + t)}{4 (- 1 + t)} = \frac{15}{4 (- 1 + t)}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 s (- 1 + t)}{4 (- 1 + t)} = \frac{15}{4 (- 1 + t)}$

Rewrite the expression.

$\frac{s (- 1 + t)}{- 1 + t} = \frac{15}{4 (- 1 + t)}$

Cancel the common factor of $- 1 + t$ .

Cancel the common factor.

$\frac{s (- 1 + t)}{- 1 + t} = \frac{15}{4 (- 1 + t)}$

Divide $s$ by $1$ .

$s = \frac{15}{4 (- 1 + t)}$

Simplify the right side.

Rewrite $- 1$ as $- 1 (1)$ .

$s = \frac{15}{4 (- 1 (1) + t)}$

Factor $- 1$ out of $t$ .

$s = \frac{15}{4 (- 1 (1) - 1 (- t))}$

Factor $- 1$ out of $- 1 (1) - 1 (- t)$ .

$s = \frac{15}{4 (- 1 (1 - t))}$

Move the negative in front of the fraction.

$s = - \frac{15}{4 (1 - t)}$

Solve for s 5-4s=4(5-st)

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