Solve for s 5s+3<s+7

$5 s + 3 < s + 7$

Step 1

Move all terms containing $s$ to the left side of the inequality.

Subtract $s$ from both sides of the inequality.

$5 s + 3 - s < 7$

Subtract $s$ from $5 s$ .

$4 s + 3 < 7$

Step 2

Move all terms not containing $s$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$4 s < 7 - 3$

Subtract $3$ from $7$ .

$4 s < 4$

Step 3

Divide each term in $4 s < 4$ by $4$ and simplify.

Divide each term in $4 s < 4$ by $4$ .

$\frac{4 s}{4} < \frac{4}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 s}{4} < \frac{4}{4}$

Divide $s$ by $1$ .

$s < \frac{4}{4}$

Simplify the right side.

Divide $4$ by $4$ .

$s < 1$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$s < 1$

Interval Notation:

$(- \infty, 1)$