Solve for s 7s+12>46-10s

$7 s + 12 > 46 - 10 s$

Step 1

Move all terms containing $s$ to the left side of the inequality.

Add $10 s$ to both sides of the inequality.

$7 s + 12 + 10 s > 46$

Add $7 s$ and $10 s$ .

$17 s + 12 > 46$

Step 2

Move all terms not containing $s$ to the right side of the inequality.

Subtract $12$ from both sides of the inequality.

$17 s > 46 - 12$

Subtract $12$ from $46$ .

$17 s > 34$

Step 3

Divide each term in $17 s > 34$ by $17$ and simplify.

Divide each term in $17 s > 34$ by $17$ .

$\frac{17 s}{17} > \frac{34}{17}$

Simplify the left side.

Cancel the common factor of $17$ .

Cancel the common factor.

$\frac{17 s}{17} > \frac{34}{17}$

Divide $s$ by $1$ .

$s > \frac{34}{17}$

Simplify the right side.

Divide $34$ by $17$ .

$s > 2$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$s > 2$

Interval Notation:

$(2, \infty)$