Solve for s p=2sq+2sr

$p = 2 s q + 2 s r$

Step 1

Rewrite the equation as $2 s q + 2 s r = p$ .

$2 s q + 2 s r = p$

Step 2

Factor $2 s$ out of $2 s q + 2 s r$ .

Factor $2 s$ out of $2 s q$ .

$2 s (q) + 2 s r = p$

Factor $2 s$ out of $2 s r$ .

$2 s (q) + 2 s (r) = p$

Factor $2 s$ out of $2 s (q) + 2 s (r)$ .

$2 s (q + r) = p$

Step 3

Divide each term in $2 s (q + r) = p$ by $2 (q + r)$ and simplify.

Divide each term in $2 s (q + r) = p$ by $2 (q + r)$ .

$\frac{2 s (q + r)}{2 (q + r)} = \frac{p}{2 (q + r)}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 s (q + r)}{2 (q + r)} = \frac{p}{2 (q + r)}$

Rewrite the expression.

$\frac{s (q + r)}{q + r} = \frac{p}{2 (q + r)}$

Cancel the common factor of $q + r$ .

Cancel the common factor.

$\frac{s (q + r)}{q + r} = \frac{p}{2 (q + r)}$

Divide $s$ by $1$ .

$s = \frac{p}{2 (q + r)}$