Solve for s (s+1)/4=4/8

$\frac{s + 1}{4} = \frac{4}{8}$

Multiply both sides of the equation by $4$ .

$4 \frac{s + 1}{4} = 4 (\frac{4}{8})$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$4 \frac{s + 1}{4} = 4 (\frac{4}{8})$

Rewrite the expression.

$s + 1 = 4 (\frac{4}{8})$

Simplify the right side.

Simplify $4 (\frac{4}{8})$ .

Cancel the common factor of $4$ .

Factor $4$ out of $8$ .

$s + 1 = 4 \frac{4}{4 (2)}$

Cancel the common factor.

$s + 1 = 4 \frac{4}{4 \cdot 2}$

Rewrite the expression.

$s + 1 = \frac{4}{2}$

Divide $4$ by $2$ .

$s + 1 = 2$

Move all terms not containing $s$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$s = 2 - 1$

Subtract $1$ from $2$ .

$s = 1$