Solve for s s^2+9s+18=0

$s^{2} + 9 s + 18 = 0$

Step 1

Factor $s^{2} + 9 s + 18$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $18$ and whose sum is $9$ .

$3, 6$

Write the factored form using these integers.

$(s + 3) (s + 6) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$s + 3 = 0$

$s + 6 = 0$

Step 3

Set $s + 3$ equal to $0$ and solve for $s$ .

Set $s + 3$ equal to $0$ .

$s + 3 = 0$

Subtract $3$ from both sides of the equation.

$s = - 3$

Step 4

Set $s + 6$ equal to $0$ and solve for $s$ .

Set $s + 6$ equal to $0$ .

$s + 6 = 0$

Subtract $6$ from both sides of the equation.

$s = - 6$

Step 5

The final solution is all the values that make $(s + 3) (s + 6) = 0$ true.

$s = - 3, - 6$

Solve for s s^2+9s+18=0

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