Solve for s s-8>9s+8

$s - 8 > 9 s + 8$

Move all terms containing $s$ to the left side of the inequality.

Subtract $9 s$ from both sides of the inequality.

$s - 8 - 9 s > 8$

Subtract $9 s$ from $s$ .

$- 8 s - 8 > 8$

Move all terms not containing $s$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$- 8 s > 8 + 8$

Add $8$ and $8$ .

$- 8 s > 16$

Divide each term in $- 8 s > 16$ by $- 8$ and simplify.

Divide each term in $- 8 s > 16$ by $- 8$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 8 s}{- 8} < \frac{16}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 s}{- 8} < \frac{16}{- 8}$

Divide $s$ by $1$ .

$s < \frac{16}{- 8}$

Simplify the right side.

Divide $16$ by $- 8$ .

$s < - 2$

The result can be shown in multiple forms.

Inequality Form:

$s < - 2$

Interval Notation:

$(- \infty, - 2)$

Solve for s s-8>9s+8

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