Solve for s s(s-1)=2

$s (s - 1) = 2$

Simplify $s (s - 1)$ .

Simplify by multiplying through.

Apply the distributive property.

$s \cdot s + s \cdot - 1 = 2$

Simplify the expression.

Multiply $s$ by $s$ .

$s^{2} + s \cdot - 1 = 2$

Move $- 1$ to the left of $s$ .

$s^{2} - 1 \cdot s = 2$

Rewrite $- 1 s$ as $- s$ .

$s^{2} - s = 2$

Subtract $2$ from both sides of the equation.

$s^{2} - s - 2 = 0$

Factor $s^{2} - s - 2$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 2$ and whose sum is $- 1$ .

$- 2, 1$

Write the factored form using these integers.

$(s - 2) (s + 1) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$s - 2 = 0$

$s + 1 = 0$

Set $s - 2$ equal to $0$ and solve for $s$ .

Set $s - 2$ equal to $0$ .

$s - 2 = 0$

Add $2$ to both sides of the equation.

$s = 2$

Set $s + 1$ equal to $0$ and solve for $s$ .

Set $s + 1$ equal to $0$ .

$s + 1 = 0$

Subtract $1$ from both sides of the equation.

$s = - 1$

The final solution is all the values that make $(s - 2) (s + 1) = 0$ true.

$s = 2, - 1$

Solve for s s(s-1)=2

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