Solve for t -16<=8/3t

$- 16 \leq \frac{8}{3} t$

Step 1

Rewrite so $t$ is on the left side of the inequality.

$\frac{8}{3} t \geq - 16$

Step 2

Multiply each term in $\frac{8}{3} t \geq - 16$ by $\frac{3}{8}$ to eliminate the fractions.

Multiply each term in $\frac{8}{3} t \geq - 16$ by $\frac{3}{8}$ .

$\frac{8}{3} t \frac{3}{8} \geq - 16 (\frac{3}{8})$

Simplify the left side.

Combine $\frac{8}{3}$ and $t$ .

$\frac{8 t}{3} \cdot \frac{3}{8} \geq - 16 (\frac{3}{8})$

Cancel the common factor of $8$ .

Factor $8$ out of $8 t$ .

$\frac{8 (t)}{3} \cdot \frac{3}{8} \geq - 16 (\frac{3}{8})$

Cancel the common factor.

$\frac{8 t}{3} \cdot \frac{3}{8} \geq - 16 (\frac{3}{8})$

Rewrite the expression.

$\frac{t}{3} \cdot 3 \geq - 16 (\frac{3}{8})$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{t}{3} \cdot 3 \geq - 16 (\frac{3}{8})$

Rewrite the expression.

$t \geq - 16 (\frac{3}{8})$

Simplify the right side.

Cancel the common factor of $8$ .

Factor $8$ out of $- 16$ .

$t \geq 8 (- 2) \frac{3}{8}$

Cancel the common factor.

$t \geq 8 \cdot - 2 \frac{3}{8}$

Rewrite the expression.

$t \geq - 2 \cdot 3$

Multiply $- 2$ by $3$ .

$t \geq - 6$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$t \geq - 6$

Interval Notation:

$[- 6, \infty)$