Solve for t 2(t+2)-3t=-1

$2 (t + 2) - 3 t = - 1$

Step 1

Simplify $2 (t + 2) - 3 t$ .

Simplify each term.

Apply the distributive property.

$2 t + 2 \cdot 2 - 3 t = - 1$

Multiply $2$ by $2$ .

$2 t + 4 - 3 t = - 1$

Subtract $3 t$ from $2 t$ .

$- t + 4 = - 1$

Step 2

Move all terms not containing $t$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- t = - 1 - 4$

Subtract $4$ from $- 1$ .

$- t = - 5$

Step 3

Divide each term in $- t = - 5$ by $- 1$ and simplify.

Divide each term in $- t = - 5$ by $- 1$ .

$\frac{- t}{- 1} = \frac{- 5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{t}{1} = \frac{- 5}{- 1}$

Divide $t$ by $1$ .

$t = \frac{- 5}{- 1}$

Simplify the right side.

Divide $- 5$ by $- 1$ .

$t = 5$