Solve for t -3>-3t+6

$- 3 > - 3 t + 6$

Step 1

Rewrite so $t$ is on the left side of the inequality.

$- 3 t + 6 < - 3$

Step 2

Move all terms not containing $t$ to the right side of the inequality.

Subtract $6$ from both sides of the inequality.

$- 3 t < - 3 - 6$

Subtract $6$ from $- 3$ .

$- 3 t < - 9$

Step 3

Divide each term in $- 3 t < - 9$ by $- 3$ and simplify.

Divide each term in $- 3 t < - 9$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 t}{- 3} > \frac{- 9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 t}{- 3} > \frac{- 9}{- 3}$

Divide $t$ by $1$ .

$t > \frac{- 9}{- 3}$

Simplify the right side.

Divide $- 9$ by $- 3$ .

$t > 3$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$t > 3$

Interval Notation:

$(3, \infty)$

Solve for t -3>-3t+6

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