Solve for t -3(5-t)=18

$- 3 (5 - t) = 18$

Step 1

Divide each term in $- 3 (5 - t) = 18$ by $- 3$ and simplify.

Divide each term in $- 3 (5 - t) = 18$ by $- 3$ .

$\frac{- 3 (5 - t)}{- 3} = \frac{18}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (5 - t)}{- 3} = \frac{18}{- 3}$

Divide $5 - t$ by $1$ .

$5 - t = \frac{18}{- 3}$

Simplify the right side.

Divide $18$ by $- 3$ .

$5 - t = - 6$

Step 2

Move all terms not containing $t$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- t = - 6 - 5$

Subtract $5$ from $- 6$ .

$- t = - 11$

Step 3

Divide each term in $- t = - 11$ by $- 1$ and simplify.

Divide each term in $- t = - 11$ by $- 1$ .

$\frac{- t}{- 1} = \frac{- 11}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{t}{1} = \frac{- 11}{- 1}$

Divide $t$ by $1$ .

$t = \frac{- 11}{- 1}$

Simplify the right side.

Divide $- 11$ by $- 1$ .

$t = 11$