Solve for t 3csc(t)^2=4

$3 \csc^{2} (t) = 4$

Divide each term in $3 \csc^{2} (t) = 4$ by $3$ and simplify.

Divide each term in $3 \csc^{2} (t) = 4$ by $3$ .

$\frac{3 \csc^{2} (t)}{3} = \frac{4}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 \csc^{2} (t)}{3} = \frac{4}{3}$

Divide $\csc^{2} (t)$ by $1$ .

$\csc^{2} (t) = \frac{4}{3}$

Take the square root of both sides of the equation to eliminate the exponent on the left side.

$\csc (t) = \pm \sqrt{\frac{4}{3}}$

Simplify $\pm \sqrt{\frac{4}{3}}$ .

Rewrite $\sqrt{\frac{4}{3}}$ as $\frac{\sqrt{4}}{\sqrt{3}}$ .

$\csc (t) = \pm \frac{\sqrt{4}}{\sqrt{3}}$

Simplify the numerator.

Rewrite $4$ as $2^{2}$ .

$\csc (t) = \pm \frac{\sqrt{2^{2}}}{\sqrt{3}}$

Pull terms out from under the radical, assuming positive real numbers.

$\csc (t) = \pm \frac{2}{\sqrt{3}}$

Multiply $\frac{2}{\sqrt{3}}$ by $\frac{\sqrt{3}}{\sqrt{3}}$ .

$\csc (t) = \pm \frac{2}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$

Combine and simplify the denominator.

Multiply $\frac{2}{\sqrt{3}}$ by $\frac{\sqrt{3}}{\sqrt{3}}$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{\sqrt{3} \sqrt{3}}$

Raise $\sqrt{3}$ to the power of $1$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{{\sqrt{3}}^{1} \sqrt{3}}$

Raise $\sqrt{3}$ to the power of $1$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{{\sqrt{3}}^{1} {\sqrt{3}}^{1}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\csc (t) = \pm \frac{2 \sqrt{3}}{{\sqrt{3}}^{1 + 1}}$

Add $1$ and $1$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{{\sqrt{3}}^{2}}$

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{{(3^{\frac{1}{2}})}^{2}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{3^{\frac{1}{2} \cdot 2}}$

Combine $\frac{1}{2}$ and $2$ .

$\csc (t) = \pm \frac{2 \sqrt{3}}{3^{\frac{2}{2}}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$\csc (t) = \pm \frac{2 \sqrt{3}}{3^{\frac{2}{2}}}$

Rewrite the expression.

$\csc (t) = \pm \frac{2 \sqrt{3}}{3^{1}}$

Evaluate the exponent.

$\csc (t) = \pm \frac{2 \sqrt{3}}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$\csc (t) = \frac{2 \sqrt{3}}{3}$

Next, use the negative value of the $\pm$ to find the second solution.

$\csc (t) = - \frac{2 \sqrt{3}}{3}$

The complete solution is the result of both the positive and negative portions of the solution.

$\csc (t) = \frac{2 \sqrt{3}}{3}, - \frac{2 \sqrt{3}}{3}$

Set up each of the solutions to solve for $t$ .

$\csc (t) = \frac{2 \sqrt{3}}{3}$

$\csc (t) = - \frac{2 \sqrt{3}}{3}$

Solve for $t$ in $\csc (t) = \frac{2 \sqrt{3}}{3}$ .

Take the inverse cosecant of both sides of the equation to extract $t$ from inside the cosecant.

$t = arccsc (\frac{2 \sqrt{3}}{3})$

Simplify the right side.

The exact value of $arccsc (\frac{2 \sqrt{3}}{3})$ is $\frac{π}{3}$ .

$t = \frac{π}{3}$

The cosecant function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$t = π - \frac{π}{3}$

Simplify $π - \frac{π}{3}$ .

To write $π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$t = π \cdot \frac{3}{3} - \frac{π}{3}$

Combine fractions.

Combine $π$ and $\frac{3}{3}$ .

$t = \frac{π \cdot 3}{3} - \frac{π}{3}$

Combine the numerators over the common denominator.

$t = \frac{π \cdot 3 - π}{3}$

Simplify the numerator.

Move $3$ to the left of $π$ .

$t = \frac{3 \cdot π - π}{3}$

Subtract $π$ from $3 π$ .

$t = \frac{2 π}{3}$

Find the period of $\csc (t)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

The period of the $\csc (t)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$t = \frac{π}{3} + 2 π n, \frac{2 π}{3} + 2 π n$ , for any integer $n$

Solve for $t$ in $\csc (t) = - \frac{2 \sqrt{3}}{3}$ .

Take the inverse cosecant of both sides of the equation to extract $t$ from inside the cosecant.

$t = arccsc (- \frac{2 \sqrt{3}}{3})$

Simplify the right side.

The exact value of $arccsc (- \frac{2 \sqrt{3}}{3})$ is $- \frac{π}{3}$ .

$t = - \frac{π}{3}$

The cosecant function is negative in the third and fourth quadrants. To find the second solution, subtract the solution from $2 π$ , to find a reference angle. Next, add this reference angle to $π$ to find the solution in the third quadrant.

$t = 2 π + \frac{π}{3} + π$

Simplify the expression to find the second solution.

Subtract $2 π$ from $2 π + \frac{π}{3} + π$ .

$t = 2 π + \frac{π}{3} + π - 2 π$

The resulting angle of $\frac{4 π}{3}$ is positive, less than $2 π$ , and coterminal with $2 π + \frac{π}{3} + π$ .

$t = \frac{4 π}{3}$

Find the period of $\csc (t)$ .

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Divide $2 π$ by $1$ .

$2 π$

Add $2 π$ to every negative angle to get positive angles.

Add $2 π$ to $- \frac{π}{3}$ to find the positive angle.

$- \frac{π}{3} + 2 π$

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 π \cdot \frac{3}{3} - \frac{π}{3}$

Combine fractions.

Combine $2 π$ and $\frac{3}{3}$ .

$\frac{2 π \cdot 3}{3} - \frac{π}{3}$

Combine the numerators over the common denominator.

$\frac{2 π \cdot 3 - π}{3}$

Simplify the numerator.

Multiply $3$ by $2$ .

$\frac{6 π - π}{3}$

Subtract $π$ from $6 π$ .

$\frac{5 π}{3}$

List the new angles.

$t = \frac{5 π}{3}$

The period of the $\csc (t)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$t = \frac{4 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

List all of the solutions.

$t = \frac{π}{3} + 2 π n, \frac{2 π}{3} + 2 π n, \frac{4 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

Consolidate the solutions.

Consolidate $\frac{π}{3} + 2 π n$ and $\frac{4 π}{3} + 2 π n$ to $\frac{π}{3} + π n$ .

$t = \frac{π}{3} + π n, \frac{2 π}{3} + 2 π n, \frac{5 π}{3} + 2 π n$ , for any integer $n$

Consolidate $\frac{2 π}{3} + 2 π n$ and $\frac{5 π}{3} + 2 π n$ to $\frac{2 π}{3} + π n$ .

$t = \frac{π}{3} + π n, \frac{2 π}{3} + π n$ , for any integer $n$

Solve for t 3csc(t)^2=4

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