Solve for t 4t-2+t^2=6+t^2

$4 t - 2 + t^{2} = 6 + t^{2}$

Step 1

Move all terms containing $t$ to the left side of the equation.

Subtract $t^{2}$ from both sides of the equation.

$4 t - 2 + t^{2} - t^{2} = 6$

Combine the opposite terms in $4 t - 2 + t^{2} - t^{2}$ .

Subtract $t^{2}$ from $t^{2}$ .

$4 t - 2 + 0 = 6$

Add $4 t - 2$ and $0$ .

$4 t - 2 = 6$

Step 2

Move all terms not containing $t$ to the right side of the equation.

Add $2$ to both sides of the equation.

$4 t = 6 + 2$

Add $6$ and $2$ .

$4 t = 8$

Step 3

Divide each term in $4 t = 8$ by $4$ and simplify.

Divide each term in $4 t = 8$ by $4$ .

$\frac{4 t}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 t}{4} = \frac{8}{4}$

Divide $t$ by $1$ .

$t = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$t = 2$