Solve for t 4t-3(t-2)=t+6

$4 t - 3 (t - 2) = t + 6$

Step 1

Simplify $4 t - 3 (t - 2)$ .

Simplify each term.

Apply the distributive property.

$4 t - 3 t - 3 \cdot - 2 = t + 6$

Multiply $- 3$ by $- 2$ .

$4 t - 3 t + 6 = t + 6$

Subtract $3 t$ from $4 t$ .

$t + 6 = t + 6$

Step 2

Move all terms containing $t$ to the left side of the equation.

Subtract $t$ from both sides of the equation.

$t + 6 - t = 6$

Combine the opposite terms in $t + 6 - t$ .

Subtract $t$ from $t$ .

$0 + 6 = 6$

Add $0$ and $6$ .

$6 = 6$

Step 3

Since $6 = 6$ , the equation will always be true for any value of $t$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$